Arithmetic Combination of Functions:
Just how numbers can be added, subtracted, multiplied, and divided --so can functions. Two functions can be combined to create new functions.
The domain of an arithmetic compound of functions f and g consists of all real numbers. In the case of f(x)/g(x), g(x) cannot = 0.
The picture below describes the sum, difference, product, and quotient of functions:
Examples:
Finding the Sum of Two Functions:
Find (f+g)(x) for the functions: f(x)= x+1 and g(x)= (x-1). Then evaluate the sum when x=3
(f+g)(x)= f(x)+ g(x) Break up the equation
(x+1) + (x-1) Plug in the values for f(x) and g(x)
x+x+1-1 Add
= 2x Final answer
Solve when x=3:
(f+g)(3)= 2(3) = 6
Finding the Difference of Two Functions:
Find (f-g)(x) for the functions: f(x)= (x+1) and g(x)= (x-1). Then evaluate the sum when x=3
(f-g)(x)= f(x) - g(x) Break up the equation
(x+1) - (x-1) Plug in the values for f(x) and g(x)
x- x+1+1 Add
= 2 Final answer
Solve when x=3:
(f-g)(3)= (3+1) - (3-1)
4-3+1
1+1= 2
Finding the Product of Two Functions:
Find (f+g)(x) for the functions: f(x)= x+1 and g(x)= (x-1). Then evaluate the sum when x=3
(f*g)(x)= f(x) * g(x) Break up the equation
(x+1) * (x-1) Plug in the values for f(x) and g(x)
x2 +x-x-1 Foil
= x2 -1 Final Answer
Solve when x=3:
(f*g)(3)= x2 -1
(3)2 -1
9-1
=8
Finding the Quotient of Two Functions:
Find (f/g)(x) for the functions: f(x)= x+1 and g(x)= (x-1). Then evaluate the sum when x=3
(f/g)(x)= f(x) / g(x) Break up the equation
(x+1) / (x-1) Plug in the values for f(x) and g(x)
= (x+1)/(x-1) Final Answer
The domain of this function is all real numbers except x=1 (since the denominator cannot equal zero).
Written in interval notation, the domain is: (-∞, 1) U (1, ∞)
For more helpful information regarding the combination of functions, see the following videos:
By: Allison Davis, 9/25/12
im still having trouble figuring out if the function is even/odd or neither.
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